Answer:
- C-B
- C-C
- C-N
- C-O
- C-F
Explanation:
As we move along to the <u>right in the same period, the electronegativity</u> and <u>the effective nuclear charge values are higher.</u>
The tendency is that <em>the higher these values are, the shorter the bonds will be</em>.
With that information in mind, and looking at the periodic table, the order would be:
- C-B
- C-C
- C-N
- C-O
- C-F
Where the C-F bond is the shortest among them.
Use the equation q=ncΔT.
q= heat absorbed our released (in this case 1004J)
n= number of moles of sample ( in this case 2.08 mol)
c=molar heat capacity
ΔT=change in temperature (in this case 20°C)
You have to rewrite the equation for c.
c=q/nΔT
c=1004J/(2.08mol x 20°C)
c=24.1 J/mol°C
I hope this helps
