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AVprozaik [17]
4 years ago
6

An investing group has $50,000 to invest. They put the money in an account that has an annual interest rate of 6%, compounded mo

nthly. How much money will the group have at the end of 10 years?
Mathematics
1 answer:
natka813 [3]4 years ago
4 0

Answer:

Use the formula for compound interest to determine the amount of money in each ... An investing group has $50,000 to invest. They put the money in an account that compounds interest ... How much money will the group have at the end of 10 years? 20. Interest is compounded quarterly at Money Bank at a rate of 5.5%.

I don't know if this helps

If it doesn't please don't delete it

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What is 4/3 divided by 5/3
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How does identifying the part in the whole help you write the percent proportion
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How many permutations of three items can be selected from a group of six? Use the letters A, B, C, D, E, and F to identify the i
pishuonlain [190]

Answer:

In total, 120 permutations of three items can be selected from a group of six distinct elements.

In particular, there are 6 ways to order three distinct items.

\begin{aligned}\rm B-D-F \\ \rm B-F-D \\ \rm D-B-F \\ \rm D-F-B \\ \rm F-B-D \\ \rm F-D-B\end{aligned}.

Step-by-step explanation:

The formula \displaystyle P(n,\, r) = \frac{n!}{(n - r)!} = n \, (n - 1) \cdots (n - r + 1) gives the number of ways to select and order r items from a group of n distinct elements.

To select and order three items from a group six distinct elements, let n = 6 and r = 3. Apply the formula:

\begin{aligned} P(6,\, 3) &= \frac{6!}{(6 - 3)!} = \frac{6!}{3!} \\ &= \frac{6 \times 5 \times 4 \times 3\times 2 \times 1}{3 \times 2 \times 1} \\ &= 6 \times 5 \times 4 = 120 \end{aligned}.

In other words, there are 120 unique ways to select and order three items (select a permutation of three items) from a group of six distinct elements.

Consider: what's the number of ways to order three distinct items? That's the same as asking: how many ways are there to select and order three items from a group of three distinct elements? Let n =3 and r = 3. Apply the formula for permutation:

\begin{aligned} P(3,\, 3) &= \frac{3!}{(3 - 3)!} = \frac{3!}{0!} && \left(\text{$0! = 1$ by convention.}\right) \\ &= 3! = 3 \times 2\times 1 \\ &= 6\end{aligned}.

To find the permutations, start by selecting one element as the first of the list. A tree diagram might be helpful. Refer to the attachment for an example.

4 0
4 years ago
Is this a direct variation? 4y=x
Sergeu [11.5K]
Google it is easy
sorry
5 0
4 years ago
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