1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,
6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*
=
(
)
Answer:
So 912$ is 58% of 1584 $
Step-by-step explanation:
Where is the equation? x=12?
2×+7=27
2×-7=27-7
2× =20
2/× =20/2
× = 10
2(10)+7=27
3×+1=28
3×-1=28-1=27
3× =27
3/× =27/3
× =9
3(9)+1=28
27 does not equal 28
so no