8x^3-28x+61/2x+5
4x^2-10x+11 with a remainder of 6
Not sure if there is supposed to be a remainder but there is one
So for this problem we have to create a common denominator by multiplying 3-x to all of the expressions. So we have 2(3-x)/(3-x)-x(3-x)/(3-x)-1/(3-x) and then we simplify to get (x^2-5x+5)/(3-x) so C.
Answer:
56/45 or 1 11/45
Step-by-step explanation:
change to improper fractions and multiply the first by the reciprocal of the second
÷
=
·
= 
45 goes into 56 1 time with a remainder of 11
Answer:
D
Step-by-step explanation:
(-8)^-2 would be 1/-64 not 1/64