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3 years ago

What is the value of y? PLEASE EXPLAIN 8.5 = y/3 <------ Fraction

Mathematics

1 answer:

NISA [10]3 years ago

5 0

Answer:

y=25.5

Step-by-step explanation:

To find y, you need to get it by itself. Ask yourself, what is being done to y, then to undo that, do the opposite. For example, if 3 was added to y, you would need to subtract 3 to cancel out the 3. In this case, what is being done to y? It's being divided by 3. So, you multiply by 3 to cancel that out. Whatever you do to one side of an equation, you also have to do to the other. So,

8.5= $\frac{y}{3}$ Multiply both sides by 3

3(8.5) = 3( $\frac{y}{3}$ ) multiply on the left side, and on the right side the 3s cancel out

25.5=y

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Answer:

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4 years ago

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A bank loaned out $19,500, part of it at the rate of 11% annual interest, and the rest at 7% annual interest. The total interest

Morgarella [4.7K]

The amount loaned at the interest rate of 11% is $3000.

The amount loaned at the interest rate of 7% is $16,500

<h3>What are the linear equations that represent the question?
a + b = 19500 equation 1</h3>

0.11a + 0.07b = 1485 equation 2

Where:

a = amount loaned at the interest rate of 11%

b = = amount loaned at the interest rate of 7%

<h3>How much was loaned at 11% and 7%</h3>

In order to determine how much was loaned at 7%, take the following steps:

Multiply equation 1 by 0.11:

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Subtract equation 2 from equation 3:

0.04b = 660

Divide both sides by 0.04:

b = 16,500

Subtract 16,500 from 19,500 :

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2 years ago

Squad root of 130 by using the Babylonian method. Let 11.5 be initial.

tangare [24]

The Babylonian method for approximating square roots is the recursive method given by:

Given:

x0≈k−−√
x
0
≈
k

Then:

xn+1=x2n+k2xn
x
n
+
1
=
x
n
2
+
k
2
x
n

where k
k
is the number for which we are approximating the square root.

So, armed with this formula, let's now answer the given questions:

1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.

We will use 15 digits of precision here since it is not stated how many iterations to carry out:

x0=11.5
x
0
=
11.5

x1≈11.4021739130435
x
1
≈
11.4021739130435

x2≈11.4017542587143
x
2
≈
11.4017542587143

x3≈11.4017542509914
x
3
≈
11.4017542509914

x4≈11.4017542509914
x
4
≈
11.4017542509914

Thus, with 15 digits of accuracy, we may state:

130−−−√≈11.4017542509914
130
≈
11.4017542509914

2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?

The next result here is approximately:

x1=10.72622+1152⋅10.7262≈10.7238055620816
x
1
=
10.7262
2
+
115
2
⋅
10.7262
≈
10.7238055620816

3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?

The next result here is:

x1=7.82+582⋅7.8=7.6179487¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
x
1
=
7.8
2
+
58
2
⋅
7.8
=
7.6
179487
¯

4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?

The next result here is:

x1=82+752⋅8=8.6875
x
1
=
8
2
+
75
2
⋅
8
=
8.6875

6 0

3 years ago