Answer:
1,145,375 cm³
Step-by-step explanation:
Like with an earlier question you had, there is a chunk missing. If that chunk was filled in, this would be a 205 * 70 * 85 rectangular prism.
205 * 70 * 85
17,425 * 70
1,219,750
The cut out chunk is a 25 * 70 * 85 triangular prism.
1/2 (25 * 70 * 85)
1/2(2,125 * 70)
1/2(148,750)
74,375
Now that we know what the cut-out chunk is, subtract that from the first value we got.
1,219,750 -74,375
1,145,375 cm³
The volume of the Canadian Post mailbox is 1,145,375 cm³.
I’m not sure about angle Q but angle R would be the same it would be 74 I’m pretty sure
Answer:
55.5 u^2
Step-by-step explanation:
Split the quadrilateral into 2 triangles. There are two ways to do this, but I'm only doing one of them.
On the 5-11 triangle, use the two of the lengths and plug them into the triangle area formula. (L x W)/2 = A
5-11 triangle area: 27.5
Do the same for the 7-8 triangle. Plug it into the same formula.
7-8 triangle area: 28
Add the two areas. 27.5 + 28 = 55.5
Answer:
Step-by-step explanation:
3 Triangle
4 Quadrilateral
5 Pentagon
6 Hexagon
7 Heptagon
8 Octagon
9 Nonagon
10 Decagon