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LenaWriter [7]
4 years ago
15

How do you solve the function 5x-4=-2(3x+2)

Mathematics
2 answers:
bogdanovich [222]4 years ago
5 0
5x - 4 = -2 (3x + 2)
Expand the bracket
5x - 4 = -6x - 4
11x = 0
x = 0/11 = 0

Hope it helped!
NemiM [27]4 years ago
3 0
5x-4=-2(3x+2)
5x-4= -6x-4
5x+6x= -4+4
11x=0
X=0/11
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Someone help please.
malfutka [58]

Answer:

$27

Step-by-step explanation:

If the table was marked up 125%, you can find the retail price of it this way:

20 + 1.25(20) = retail price

$45 = retail price.

To find 40% off of that, use

$45 - .4($45) = sale price

$27 = sale price (aka discount price)

5 0
3 years ago
2x= -10 what is x??????
Reptile [31]
The correct answer is X = -5
5 0
3 years ago
What is 4.125 to the nearest whole number?
Elis [28]
When you are rounding numbers, if the integer to the right is <5, then you keep your rounding number.  If it is >5, then you add 1 place value to your rounding number.

Therefore, if you are trying to round 4.125 to the nearest whole number, you are trying to round it to the ones place, or where the 4 is.  
Because 1<5, 4.125 rounded to the nearest whole number is 4.
5 0
4 years ago
Read 2 more answers
Solve for x............
Yanka [14]

Step-by-step explanation:

because angle A and C are similar, so

9x-8=28

9x=36

x=4

5 0
3 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
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