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iogann1982 [59]

2 years ago

8

A movie theater sends out a coupon for % off the price of a ticket. Write an equation for the situation, where y is the price

of the ticket with the coupon, and x is the original price of the ticket.65

1 answer:

natali 33 [55]2 years ago

5 0

The orginal price is 65

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Algebraic factorisation simplification long question

qwelly [4]

Answer:Algebra Questions, for Grade 10, on simplifying, factoring, evaluating expressions and solving equations are presented along with their answers

Step-by-step explanation:

I do not know if this helps or not but here you go!

3 0

2 years ago

Darius is a broker who earns a $68,000 annual salary, a 3.15% commission on his clients’ investments, and a fee of $4.25 for eac

taurus [48]

Answer:

$187,244

Step-by-step explanation:

$68,000 annual salary + 3.15% commission + fee of $4.25 per transaction

$68,000 + 0.0315 * $3,600,000 + $4.25 * 1,375 =

= $187,243.75

Answer: $187,244

4 0

3 years ago

When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil

Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

90% of the students passed, hence $p = 0.9$ .

The professor randomly selected 10 exams, hence $n = 10$ .

Item a:

The probability is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937$

$P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874$

$P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487$

Then:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298$

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

$P(X < 5) = 0.0001$

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0

1 year ago

I am thinking of a number that is greater than 142 rounded to the nearest 100 but has a 5 in the ones place! What’s my number!?

Darina [25.2K]

I think your number would be 542

6 0

3 years ago

The equation of line q is y =

shtirl [24]

These are not the exact numbers but just plug in the numbers of yours Because we know that q is a perpendicular line to p we know that its slope is the negative reciprocal of the slope of p. So its slope is 7/10. Now we just need to find its y-intercept. To do that we write what we know about line q. So we know that the equation for line q looks like:

y = (7/10)x + b

We also know that q passes through the point (8,7), so we now plug that in and solve for b:

7 = (7/10)(8) + b
7 - (56/10) = b
(70/10) - (56/10) = b
14/10 = 7/5 = b

So now that we have solved for the y-intercept, we know that the equation for line q is:

y = (7/10)x + 7/5

3 0

2 years ago