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4 years ago

Abcdefghijklmnopqrstuvwxyz

Mathematics

2 answers:

nignag [31]4 years ago

7 0

Answer:

the annswer is b

Step-by-step explanation:

bbbb 44h . ddeee

Burka [1]4 years ago

4 0

Answer:

qwerty in the answer

Step-by-step explanation:

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46.The function f graphed above is the function f(x) = log2(x) + 2 for x > 0. Find a formula for the inverse of this function

pantera1 [17]

Answer:

The inverse for log₂(x) + 2 is - log₂x + 2.

Step-by-step explanation:

Given that

f(x) = log₂(x) + 2

Now to find the inverse of any function we put we replace x by 1/x.

f(x) = log₂(x) + 2

f(1/x) =g(x)= log₂(1/x) + 2

As we know that

log₂(a/b) = log₂a - log₂b

g(x) = log₂1 - log₂x + 2

We know that log₂1 = 0

g(x) = 0 - log₂x + 2

g(x) = - log₂x + 2

So the inverse for log₂(x) + 2 is - log₂x + 2.

3 0

4 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago

What is negative three, times 4x plus 2

alexgriva [62]

-10 or X=1.25

hope this helps

4 0

3 years ago

What is the equation of the line that passes through the points (−2, 1) and (1, 10)? 3x − y = −73x − y = −53x − y = 5x + 3y = −5

djyliett [7]

The two point formula :

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The points are (-2, 1) and (1, 10)

Using the formula above :

$\begin{gathered} y-1=\frac{10-1}{1-(-2)}(x+2) \\ y-1=\frac{9}{3}(x+2) \\ y-1=3(x+2) \\ y-1=3x+6 \\ -3x+y=6+1 \\ -3x+y=7 \\ 3x-y=-7 \end{gathered}$

The answer is 3x - y = -7

7 0

1 year ago

Help please! | 2x^2 + 5x + 3 | > 0 solve the inequality

vovikov84 [41]

Factorize the quadratic.

$2x^2 + 5x + 3 = (2x + 3) (x + 1)$

We have $|ab| = |a||b|$ , so

$|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0$

Now, both $|2x+3|\ge0$ and $|x+1|\ge0$ (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

$(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1$

So the solution to the inequality is the set

$\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}$

3 0

2 years ago