I haven't done these problems in a really long time, so there's a chance that my answer might be wrong. I hypothesize that the correct answer is C.
Answer:i would say 1
Step-by-step explanation:
<span><span>The sum of a squared and b is given by

</span>7 times the sum of a squared and b is given by
</span><span>
while 4 times the sum of a squared and b is given by
</span>

Therefore, <span>7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

</span>
The length and width of rectangular traffic sign are 40 and 30 inches respectively
<h3><u>Solution:</u></h3>
Given that,
Perimeter of rectangular traffic sign = 140 inches
Let length and width be denoted as ‘L’ and ‘B’ respectively
Given that length is 10 inches longer than its width
L = 10 + B
<em><u>The perimeter of rectangle is given as:</u></em>
Perimeter = 2( L + B)
On substituting the values, we get
140 = 2(10 + B + B)
140 = 2(10 + 2B)
140 = 20 + 4B
B = 30
Therefore, the length is L = 10 + 30 = 40
Hence the dimensions length and width of the rectangle are 40 and 30 inches respectively.
Answer:
<h2>−9a³ − a² + 12a</h2>
Step-by-step explanation:
3a(a²-3a+4)-4(3a³-2a²) = 3a³ − 9a² + 12a − 12a³ + 8a²
= (3a³ − 12a³) + (− 9a² + 8a²) + 12a
= −9a³ − a² + 12a