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ehidna [41]
3 years ago
5

Which is closest to the area of the shaded region in the figure, in square units?

Mathematics
2 answers:
quester [9]3 years ago
8 0
The third option : 228
:)
The answer on top is 100% correct
MrMuchimi3 years ago
7 0
We know the width of the rectangle is 24 and that the height is 12 which makes it have a area of 288. 
The area of the circle is pie 6^2 or 36pi or 113. We have two of these circles having the total area of the circles 226. To find the are of the shaded reigon we subtract. 288-226=62.
62 is the answer or the second one.:)
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Circle X with a radius of 6 units and circle Y with a radius of 2 units are shown. Which steps would prove the circles similar?
SSSSS [86.1K]

Answer:

See bolded below.

Step-by-step explanation:

Take a look at the attachment below. It represents circle x and y, with respect to each of their radii. In each of the options we are given, we would have to translate and dilate the circles, by a fixed scale factor -

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Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How man
nasty-shy [4]
To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy. 

Max was on vacation twice as long as Jared. We can interpret this as  M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, <span>M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
</span><span>M + J + W = 21 [From the old list]
</span>J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one. 
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
<span>(7/2)M = 21 
</span>
Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
(\frac{2}{7})* (\frac{7}{2}m)= (\frac{2}{7})*(21)
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
<span>J = (1/2)M 
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days 
</span>
Wesley was on vacation twice as long as Max so...  W = 2M 
W= 2*6
W = 12
Wesley was on vacation for 12 days. 

Let's double check our answer:
M + J + W = 21 days<span>6 + 3 + 12 = 21   
The numbers work out so the math is correct. Hope this helps and makes sense!</span>
6 0
4 years ago
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