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vaieri [72.5K]
3 years ago
12

Plz help im an idiot

Mathematics
2 answers:
Kruka [31]3 years ago
6 0

Answer:

3- 42, 4- 137

Step-by-step explanation:

<1+<2+x=180

93+45+x=180

x=180-93-45

x=42

<1+<2+<3=180

43+106+<3=180

<3=180-106-43

<3=31

<3+x=180

43+x=180

x=180-43

x=137

MrMuchimi3 years ago
5 0

Answer:

3.)138

4.) 149

Step-by-step explanation:

you add the two inside measures together.

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the length of the side of two squares are 4cm and 6cm .Find in its simplest form the ratio of them perimeter and area​
Zolol [24]

Length of side of a square = 4cm

Perimeter of this square :

=   \tt4 \times side

= \tt 4  \times 4

=  \tt16 \: cm

Thus, the perimeter of this square = 16 cm

Length of side of the second square = 6 cm

Perimeter of this square :

= \tt 4 \times side

=  \tt4 \times 6

= \tt 24 \: cm

Thus, the perimeter of this square = 24 cm

Ratio of the perimeters of both the squares :

=  \tt16 : 24

=  \tt \frac{16}{24}

=  \tt \frac{16 \div 4}{24 \div 4}

= \tt  \frac{4}{6}

= \tt  \frac{4 \div 2}{6 \div 2}

= \tt  \frac{2}{3}

Thus, the ratio of the perimeter of both the squares = 2:3

Length of side of the first square = 4 cm

Area of this square :

= \tt side \times side

= \tt 4  \times 4

= \tt  {16cm}^{2}

Thus, the area of the first square = 16 cm²

Length of side of the second sqaure = 6 cm

Area of this square :

=  \tt \: side \times side

=  \tt 6 \times 6

=   \tt{36cm}^{2}

Thus, the area of the second square = 36 cm²

Ratio of the areas of the two squares :

=  \tt16 : 36

= \tt  \frac{16 \div 4}{36 \div 4}

= \tt   \frac{4}{9}

=  \tt4 : 9

Thus, the ratio of the areas of the two squares = 4:9

Therefore, the ratio of the perimeter of the squares = <u>2:3</u> and the ratio of the areas of these squares = <u>4:9</u>.

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