Question:
Which is equivalent to
after it has been simplified completely?
Answer:

Step-by-step explanation:
Given

Required
Simplify
We start by splitting the square root

Replace 180 with 36 * 5

Further split the square roots


Replace power of x; 11 with 10 + 1

From laws of indices; 
So, we have


Further split the square roots

From laws of indices; 
So, we have



Rearrange Expression


From laws of indices; 
So, we have



<em>The expression can no longer be simplified</em>
Hence,
is equivalent to 
Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
Answer:
- Option <u>B </u>is correct i.e. <u>2</u><u>1</u>
Step-by-step explanation:
In the question we're provided with an equation that is :
And we are asked to find the solution for the equation .
<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>
<u>
</u>
Multiplying by 7 on both sides :

On further calculations , we get :

- <u>Therefore</u><u> </u><u>,</u><u> </u><u>solution</u><u> </u><u>for</u><u> equation</u><u> </u><u>is </u><u>2</u><u>1</u><u> </u><u>.</u><u>That </u><u>means</u><u> </u><u>option </u><u>B </u><u>is </u><u>the </u><u>correct</u><u> answer</u><u>.</u>
<u>Verifying</u><u> </u><u>:</u>
We are verifying our answer by substituting value of v in the equation given in question :

Putting value of v :

By dividing 21 with 7 , we get :



- <u>Therefore</u><u> </u><u>,</u><u> </u><u>our </u><u>answer</u><u> is</u><u> valid</u><u> </u><u>.</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>