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Rama09 [41]
2 years ago
12

I need help with this question.

Mathematics
1 answer:
marshall27 [118]2 years ago
3 0
That seems so hard, sending prayers and brain cells to you.
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PLEASE HELP!! Dee bought 6 dolls and 2 toy trains for $55. At the same prices, Joy bought 4 dolls and 7 toy trains for $65. What
GuDViN [60]

Answer:

The cost of 1 doll   =  $ 7.5

and The  Cost of 1 toy train =   $ 5

Step-by-step explanation:

Let the price of 1 doll  = $ x

The price of  1 toy train  = $ y

Now, according to the question:

6 x + 2 y  = $ 55

and  4 x   + 7 y = $ 65

Solving the given system of equation,

From (1), we get

x= \frac{55 - 2y}{6}

4 ({\frac{55 - 2y}{6}} )  + 7y = 65

or, solving for y , we get

110y - 4y + 21 y = 195

or, 17 y = 85

⇒ y= 85/17 = 5

This implies :  6 x + 2 (5)   =55

or, 6x = 55 - 10 = 45

or, x =  45/ 6 = 15/2

Hence, the cost of 1 doll  = x = $ 7.5

and the Cost of 1 toy train =  y = $ 5

5 0
3 years ago
what is the probability of rolling 15 with a pair of dice? answer in likely, unlikely, equally likely, or impossible
aleksley [76]

it is clearly impossible

8 0
2 years ago
Find the Exponential Regression using the table. Write the initial amount, common ratio, and equation for the table.
Ipatiy [6.2K]

Answer:

Initial amount;

2110.6

Common ratio;

0.0201

Equation;

y=2110.6e^{0.0201x}

Step-by-step explanation:

In this scenario, the  month represents the independent variable x while the membership amount represents the dependent variable y.

The analysis is performed in Ms. Excel. The first step is to obtain a scatter plot of the data then finally inserting an exponential trend line to obtain the required equation.

The Ms. Excel output is shown in the attachment below. To obtain the initial amount we substitute x = 0 in the equation. On the other hand, the common ratio is the exponent in the equation.

7 0
2 years ago
Please help me with my homework idk if it is right or wrong
jeka57 [31]
Q1: 7×6 = 42
Q2: 42×1/8 = 42/8 = 5.25 (5 1/4) in^3
Q3: (0.5)^3 = 0.5×0.5×0.5 = 0.125 m^3
Q4: 4(5/2)^2 = 4×5/2×5/2 = 4×25/4 = 25 in^3
Q5: 3(13/2)(3/2) = 117/4 = 29.25 (29 1/4) in^3
Q6: (0.9)^3 = 0.729 cm^3
6 0
3 years ago
estamos construyendo una carretera que enlace los puntos a = 12 ,21 y b =(17,23) otro punto se encuentra en c =(3,9) es posible
Nadusha1986 [10]

Answer:

is not possible

Step-by-step explanation:

<u><em>The question in English is</em></u>

we are building a road that links the points a = (12 ,21) and b =(17,23) another point is in c =(3,9) it is possible that a single road allows to join these three points?

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope ab

we have

a = (12 ,21) and b =(17,23)

substitute

m=\frac{23-21}{17-12}

m=\frac{2}{5}

step 2

Find the slope ac

we have

a = (12 ,21) and c =(3,9)

substitute

m=\frac{9-21}{3-12}

m=\frac{-12}{-9}

simplify

m=\frac{4}{3}

step 3

Compare slopes ab and ac

The slopes are different

That means ----> is not possible that a single road allows to join these three points

7 0
2 years ago
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