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Elena L [17]
3 years ago
9

A 57-inch television screen has an aspect ratio of 4:3. Find the scale factor (x), find the length and width, and calculate the

Area.
please show work if you can

Mathematics
1 answer:
natulia [17]3 years ago
3 0

tv-sets are rated by the screen size and the screen size comes from the length of its diagonal.

so a 57" TV has a 57" diagonal.

Check the picture below.

\bf \stackrel{length}{4\left( \cfrac{57}{5} \right)}\implies \cfrac{228}{5}\implies 45\frac{3}{5}~\hfill \stackrel{width}{3\left( \cfrac{57}{5} \right)}\implies \cfrac{171}{5}\implies 34\frac{1}{5} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Area}{\cfrac{228}{5}\cdot \cfrac{171}{5}}\implies \cfrac{38988}{25}\implies 1559\frac{13}{25}

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Jarred sells DVDs. His inventory shows that he has a total of 3,500 DVDs. He has 2,342 more contemporary titles than classic tit
GaryK [48]
Answer: x = 2921, y = 579

Step-by-Step Explanation:

I am assuming that we just have to Solve for ‘x’ and ‘y’.

‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles

=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)

Adding Eq. 1 and Eq. 2, we get :-

2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921

Therefore, x = 2921

Substitute value of ‘x’ in Eq. 1 :-

x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579

Therefore, y = 579

Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579
6 0
1 year ago
Your sister is getting married this summer and she has asked you to help her select a D.J.
ioda
So Dave charges 150 at first and then 10.50 per each hour, so if your sister has the party going for say "h" hours, then his total charges will then be 150 + 10.5h.

now, Marvin's Mobile Music charges 135 at first, but then is more expensive per hour is 15 bucks per each hour, so if she has a party for "h" hours, then his total charges are 135 + 15h.

now, let's check when they're both equal, at how many hours will they cost your sister the same amount.

\bf 150+10.50h=135+15h\implies 150-135=15h-10.5h
\\\\\\
15=4.5h\implies 15=4\frac{1}{2}h\implies 15=\cfrac{9}{2}h\implies \cfrac{15}{\frac{9}{2}}=h\implies \cfrac{\frac{15}{1}}{\frac{9}{2}}=h
\\\\\\
\cfrac{15}{1}\cdot \cfrac{2}{9}=h\implies \cfrac{30}{9}=h\implies \cfrac{10}{3}=h\implies 3\frac{1}{3}=h

so, 3 and a third of a hour, or 3 hours and 20 minutes, they both will cost your sister the same amount, so it wouldn't matter who's hired if the party is only 3 hours and 20 minutes long.

however, after that, the one with higher hourly rate, Marvin's, gets more expensive, and she's better off hiring the one with cheaper hourly rate.

now, you can just get some mp3s and some loud speakers and nevermind the  DJs and you do it, or she can do it, I have the macarena song if you need that one.
3 0
3 years ago
I need help plz help
VashaNatasha [74]

twice as many cats (as) dogs.

c = 2d  [not true]

Three less than twice as many cats (as) dogs.

c = 2d - 3

210 combined,

c + d = 210

Subtracting,

-d = 2d - 3 - 210

-3d = -213

d = 71

Answer: 71

7 0
3 years ago
1. Find the lengths of the sides of each triangle.
fredd [130]

Answer:

.....?....................

4 0
2 years ago
if alpha and beta are zeroes of the quadratic polynomial f(x) = x2-x-2 then find a polynomial whose zeroes are 2alpha + 1 and 2b
frosja888 [35]

Answer:

Step-by-step explanation:

Hello, as alpha and beta are zeroes of

x^2-x-2

it means that their sum is alpha+beta=1 and their product alpha*beta=-2.

The polynomial whose zeroes are 2 alpha + 1 and 2 beta + 1, means that the sum of its zeroes is 2(alpha+beta)+2=2+2=4

and the product is (2alpha+1)(2beta+1)=4 alpha*beta + 2(alpha+beta) + 1 = 4 * (-2) + 2*(1) +1 = -8 + 2 + 1 = -5. so one of these polynomials is

\Large \boxed{\sf \bf \  \ x^2-4x-5 \ \ }

Thank you.

5 0
3 years ago
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