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3 years ago

Which matrix is equal to... (picture added)

Mathematics

1 answer:

Ghella [55]3 years ago

4 0

Answer:

D $\left[\begin{array}{ccc}-6&-6.5&1.7\\-2&-8.5&19.3\end{array}\right]$

Step-by-step explanation:

Two matrices are equal when they

have the same sizes (so options A and B are false)
have equal corresponding elements (so option C is false, because -6≠6, -6.5≠6.5, 1.7≠-1.7 and so on)

If in option D the second row is 2 -8.5 19.3 , then these matrix is equal to the given.

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X - 2/5 = 1/3 <br> what is x?<br> thanks x

Bogdan [553]

Isolate x. First, add 2/5 to both sides

x - 2/5 (+2/5) = 1/3 (+2/5)

x = 1/3 + 2/5

to simplify, find common denominators (15 in this case). Multiply the same number to both the denominator and numerator

(1/3)(5/5) = 5/15

(2/5)(3/3) = 6/15

x = 5/15 + 6/15

Simplify

x = 11/15

11/15 is your answer for x

hope this helps

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4 years ago

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natka813 [3]

So, I don’t speak English, but I’m trying
290:5=
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3 years ago

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A rectangular patio has a length of 12 1\2 feet and an area of 103 1\8 square feet. What is the width of the patio?

Whitepunk [10]

Answer:

8.25 feet

Step-by-step explanation:

to find the width, you divide the area by the length

103 1/8 / 12 1/2 = 8.25

Give brainliest, please!
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2 years ago

PLEASE HELP I NEED TO DO THIS BUT I DON’T KNOW HOW

galben [10]

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E5_1%20%7B%20%5Cfrac%7BlnR%7D%7B%20R%5E%7B2%7D%20%20%7D%20%5C%2C%20dR%20"

alex41 [277]

Integrate by parts, setting

$\begin{matrix}u=\ln R&&\mathrm dv=\dfrac{\mathrm dR}{R^2}\\\mathrm du=\dfrac{\mathrm dR}R&&v=-\dfrac1R\end{matrix}$

So the integral is

$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\dfrac{\ln R}R\bigg|_{R=1}^{R=5}+\int_1^5\frac{\mathrm dR}{R^2}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\left(\frac{\ln5}5-\frac{\ln1}1)-\frac1R\bigg|_{R=1}^{R=5}$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=-\frac{\ln5}5-\left(\frac15-1\right)$
$\displaystyle\int_1^5\frac{\ln R}{R^2}\,\mathrm dR=\frac15(4-\ln5)$

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4 years ago