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Vitek1552 [10]
3 years ago
6

The temperature in Montreal, Canada went from 0° Celsius to 11.7° Celsius in a six hour period. If the temperature increased at

a constant rate, how many degrees did the temperature rise per hour?
Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
Rate=\frac{\Delta temp}{\Delta time}
Rate=\frac{temp_{2}-temp_{1}}{time_{2}-time_{1}}
Rate=\frac{11.7\°-0\°}{6hr-0hr}
Rate=\frac{11.7\°}{6hr}
Rate=1.95\frac{\°}{hr}
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From the question, we are to determine the roots of the given equation

The given equation is

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Using the formula method,

x =\frac{-b \pm \sqrt{b^{2}-4ac } }{2a}

In the given equation,

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Putting the values into the formula,

x =\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(2) } }{2(1)}

x =\frac{5 \pm \sqrt{25-8} }{2}

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x =\frac{5 + \sqrt{17} }{2} OR x =\frac{5 - \sqrt{17} }{2}

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x =\frac{9.12}{2} OR x =\frac{0.88}{2}

x = 4.56 OR x = 0.44

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Learn more on Quadratic equation here: brainly.com/question/8649555

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2 years ago
About 12% of individuals write with their left hands. If a class of 130 students meets in a classroom with 130 individual desks,
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0.1019

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