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Vitek1552 [10]
3 years ago
6

The temperature in Montreal, Canada went from 0° Celsius to 11.7° Celsius in a six hour period. If the temperature increased at

a constant rate, how many degrees did the temperature rise per hour?
Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0
Rate=\frac{\Delta temp}{\Delta time}
Rate=\frac{temp_{2}-temp_{1}}{time_{2}-time_{1}}
Rate=\frac{11.7\°-0\°}{6hr-0hr}
Rate=\frac{11.7\°}{6hr}
Rate=1.95\frac{\°}{hr}
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soldier1979 [14.2K]

Answer:

x=2(twice)

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Step-by-step explanation:

This question can be solved using substitution method

So let's solve

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Let's substitute the value of x into (1)

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6 0
4 years ago
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IrinaK [193]
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Explanation:

write as : <span>y=50000<span><span>(0.8)</span>x</span></span>

Taking logs:

<span><span>log<span>(y)</span></span>=<span>log<span>(50000)</span></span>+<span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span></span>

But <span>log<span>(.<span><span>(0.8)</span>x</span>.)</span></span> is the same as <span>x<span>log<span>(0.8)</span></span></span>

Thus
<span>x=<span><span><span>log<span>(y)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)

</span></span></span></span></span>Now swap the x'x and the y's giving:<span><span><span><span><span>
</span></span></span></span></span>

<span>y=<span><span><span>log<span>(x)</span></span>−<span>log<span>(50000)</span></span></span><span>log<span>(0.8<span>)

my teacher helped a little bit


</span></span></span></span></span>

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