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3 years ago

What’s 24 times 40 equals

Mathematics

2 answers:

Aleksandr-060686 [28]3 years ago

3 0

24 times 40 equals 960.

swat323 years ago

3 0

24 times 40 equals 960
hope it helps

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The lengths of the two sides of a triangle (not necessarily a right triangle) are 1.00 meters and 3.54 meters. The sine of the a

DerKrebs [107]

Answer:

sin B= 0.096288

B = 5.525°

Step-by-step explanation:

Consider ΔABC as shown in figure attached

From figure:

a = 1 m

b = 3.54 m

sin A = 0.0272

sin B = ?

Using the sine rule for non-right-angle triangle

$\\\frac{a}{sin\, A}=\frac{b}{sin\,B}\\\\sin\,B=\frac{b(sin\,A)}{a}\\\\sin\,B=\frac{(3.54)(0.0272)}{1}\\\\sin\,B=0.096288\\\\B= 5.525^o$

4 0

3 years ago

Out of a group of 120 students that were surveyed about winter sports 28 said they ski 53 said they snowboard Sixteen of the stu

hjlf

Answer:

P ( snowboard I ski) = 0.5714

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Ski

Event B: Snowboard.

28 out of 120 students ski:

This means that $P(A) = \frac{28}{120} = 0.2333$

16 out of 120 do both:

This means that $P(A \cap B) = \frac{16}{120} = 0.1333$

P ( snowboard I ski)

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1333}{0.2333} = 0.5714$

P ( snowboard I ski) = 0.5714

7 0

3 years ago

Read 2 more answers

How do i solve that question?

yawa3891 [41]

a) The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

b) The integrating factor for the ordinary differential equation is $-\frac{1}{x}$ .

The particular solution of the ordinary differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ .

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

$6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C$

Where $C$ is the integration constant.

By table of integrals we find the solution for each integral:

$-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C$

If we know that $x = 0$ and $y = 1$ , then the integration constant is $C = -2$ .

The solution of this ordinary differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$