The graph of g(x) = f(-5x+10) is given in the figure.
<h3>What is a graph?</h3>
A diagram showing the relation between two variable quantities,each measured along one of a pair of axes at right angles.
It is given that f(x) = x^2
and g(x ) = f(-5x+10)
Now putting the value of f(x) in g(x) we get,
g(x) = f(-5x+10) = (-5x+10)^2
So, g(x) = (-5x+10)^2
now, making the table for g(x),
<u><em>x </em></u><u>g(x)</u>
0 100
1 81
2 0
3 25
4 100
5 225
Hence,the graph of g(x) = f(-5x+10) is given in the figure.
More about graph :
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Step-by-step explanation:
(X+3)(2x_9)
3x+12_12=90_12
3x=90_12
3x=78
X=26°
Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
Answer: 348
Step-by-step explanation:
Given : Total employees work = 725
Proportion of employees are post graduate = 52%
Proportion of employees are not post graduate = 100%-52% = 48%
The number of employees were not post graduate = 48% of 725
= 0.48 x 725
= 348
Hence, the number of employees were not post graduate = 348
Factors of 18: 1; 2; 3; 6; 9; 18
Factors of 27: 1; 3; 9; 27
GCF(18; 27) = 9
<span>18 + 27 = 9 × 2 + 9 × 3 = 9 × (2 + 3) </span>