2 years ago

What is the vertex of y=1/2(x+4)^2+1

Mathematics

1 answer:

Margaret [11]2 years ago

6 0

i’m not sure but try googling or looking on slader

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(Ill give brainliest)

Anna007 [38]

Answer:

522

Step-by-step explanation:

3 0

2 years ago

Solve the system of equations below.

Ostrovityanka [42]

C - no solution
you take the second solution and times the entire equation by -1
then simply
and you get 0x + 0y = 20

5 0

3 years ago

Read 2 more answers

Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary

Naddik [55]

Check the picture below.

$\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
\end{cases}$

since the distance AB cannot be a negative value, thus is not -3-√(130).