<u>Answer-</u>
<em>Strip with </em><em>2.13 ft </em><em>width can be used. </em>
<u>Solution-</u>
A club swimming pool is 21 ft wide and 41 ft long.
Hence, the perimeter of the swimming pool is

The club members want a uniform width border around the pool.
They have enough material for 264 ft²
As they will cover the perimeter of the rectangular pool, so the length of the total used strip is equal to the perimeter of the swimming pool.
Let the width of the strip is x ft
So, the total area of the used strip is,

Putting the values,



Therefore, strip with 2.13 ft width can be used.
Blue to orange
6 : 5
24 : x

There are 20 orange M&M's.
Hope this helps. - M
Answer:
it will cost him £2.38
Step-by-step explanation:
bc you first multiply 4.25kg with £1.40 and that equals to 5.95
then you take 5.95 and devide it with 2.5 kg then that equals to £2.38.
I hope that this helped you.