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Kitty [74]
3 years ago
8

A locker combination has three nonzero digits, and digits cannot be repeated. If the first digit is 3, what is the probability t

hat the next digit is odd?
A. 4/9

B. 1/5

C. 1/2

D. 5/9
Mathematics
1 answer:
Vanyuwa [196]3 years ago
3 0

Answer:

1/2

Step-by-step explanation:

If the locker has 3 non zero digits, this means the digits will take values from 1 to 9. If the first digits is 3, the remaining digits can take any of the values in the set {1, 2, 4, 5, 6 7, 8, 9}

Total elements in the set = 8

Total odd numbers there = {1, 5, 7, 9} = 4 odd numbers

If the next digit is odd, probability that the next digit is odd will be Total odd numbers/Total elements in the set = 4/8 = 1/2

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What are the factors of 36?
Rashid [163]
1 2 3 4 6 9 12 18 36
5 0
3 years ago
Simplify the expression using the proper order of operations<br> 5[6 ÷ 2^2 ∙ 3 - 1]
disa [49]

The simplification of the expression 5(6 ÷ 2² × 3 - 1) using the proper order of operation is 3.75

<h3>Simplification</h3>

5(6 ÷ 2² × 3 - 1)

Bodmas

  • B - Bracket
  • O - of
  • D - division
  • M - Multiplication
  • A - Addition
  • S - Subtraction

= 5(6 ÷ 4 × 3 - 1)

= 5(6 ÷ 4 × 2)

= 5(6 ÷ 8)

= 5(0.75)

= 3.75

Learn more about simplification:

brainly.com/question/723406

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3 0
2 years ago
1. The amount of extension in an elastic spring varies directly as the weight hung on it. If a weight of 150 gm produces an exte
gregori [183]

Answer:

900 g

Step-by-step explanation:

let e be extension and w be weight

given e varies directly as w then the equation relating them is

e = kw ← k is the constant of variation

to find k use the condition w = 150 , e = 2.9 , then

2.9 = 150k ( divide both sides by 150 )

\frac{2.9}{150} = k , that is

k = \frac{29}{1500}

e = \frac{29}{1500} w ← equation of variation

when e = 17.4 , then

17.4 = \frac{29}{1500} w ( multiply both sides by 1500 )

26100 = 29w ( divide both sides by 29 )

900 = w

3 0
2 years ago
Which model represents 2 . 36 ÷ 4 ?Which model represents 2 . 36 ÷ 4 ? A. Three groups each have three tens and 4 ones. B. There
makvit [3.9K]

Answer: C. There are four groups of three tens and six ones

Step-by-step explanation:

From the options,

A. Three groups each have three tens and 4 ones.

Three tens and 4 ones equal: = (3 × 10) + (4 × 1) = 30 + 4 = 34

Therefore, 34 ÷ 3 is incorrect.

B. There are three groups of five tens and 9 ones in each group.

Five tens and 9 ones will be equal to:

= (5 × 10) + (9 × 1)

= 50 + 9 = 59

Therefore, 59 ÷ 3 is incorrect

C. There are four groups of three tens and six ones.

Three tens and six ones equal:

= (3 × 10) + (6 × 1)

= 30 + 6 = 36

Therefore, 36 ÷ 4 is correct

D. There are three groups of five tens and nine ones in each group.

Five tens and nine ones will be equal to:

= (5 × 10) + (9 × 1)

= 50 + 9 = 59

Therefore, 59 ÷ 3 is incorrect

Therefore, the correct option is C.

5 0
2 years ago
What is 2(d+9) expression
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