Here, to find the average rate of change, you would simply divide 270 by 63. And when that is done, you would get a long decimal. 4.285714285714286
And since you obviously can't put in such a long decimal as your answer, you would round it instead. Once rounded, you would end up with 4.29 (because the number after 8 is five, which rounds up, which would turn the 8 to 9.)
ANSWER
45.6cm to the nearest tenth.
EXPLANATION
The diagonal of the rectangular painting is 62cm.
The height of the painting is 42 cm.
The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.
From the Pythagoras Theorem,
The width of the painting is 45.6cm to the nearest tenth.
Part 1: Answer:
(x+1)(x+1)(x-6) = x^3 - 4x^2 - 11x - 6
Step-by-step explanation:
To make r a root, include (x-r) as a factor. (-1+1)(-1+1)(-1-6) is zero even though (-1-6) isn't.
(6+1)(6+1)(6-6) is zero.
Part 2 Answer:
Standard form: y = -x^4 + 12
Degree 4
left end goes down, right end goes down.
Step by step: apply the definitions of standard form, polynomial degree, and "end behavior". In other words, read the textbook.
Part 3: Answer: x = 3, x = 8
Step by step:
x^2-11x = -24
x^2-11x+24 = 0
(x-3)(x-8) = 0
x = 3 or x = 8
Part 4a Answer:
quotient 2x^2 + x - 3
remainder 1
Step by step:
2x^2 + x - 3
___________________
x-4 ) 2x^3 - 7x^2 - 7x + 13
2x^3 - 8x^2
__________
0 + x^2 - 7x + 13
x^2 - 4x
____________
0 - 3x + 13
- 3x + 12
______
1
Part 4b answer:
quotient 2x^2 - 6x + 2
remainder -20
Step by step: you have to know exactly what you are doing. Refer to textbook or Wikipedia.
dividend 2x^3 +14x^2 - 58x
divisor x+10
leading coefficient of divisor must be 1
write coefficients of dividend at top
write coefficients of dividend at left
| 2 14 -58 0
-10 | -20 60 -20
___________
| 2 -6 2 -20
Coefficients of quotient are 2 -6 2
Remainder is -20
quotient = 2x^2 - 6x + 2
Answer:
Explanation:
The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.
Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.
The limits of the quadratic function of general form as x approaches negative infinity or infinity, when is positive, are infinity.
That is because as the absolute value of x gets bigger y becomes bigger too.
In mathematical symbols, that is:
Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².
Two examples are:
Answer:
Area is 24
Explanation: times the length by the breath (width)