Look for a pattern to find the value of ninput output-1 -10 81 172 263 n4 44
1 answer:
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Answer:
<em>Both objects collide at t=3 in the point <9,9,9></em>
Step-by-step explanation:
<em>Collision Of Moving Objects </em>
Two objects can describe different trajectories in the space. Those trajectories can intersect in one or more points but it doesn't mean they collide. Collision occurs if they are in the same position at the same time. If we know the positions as a function of time of each object, we could try so find if, for a given time, they are in the same position.
The positions of two object are given as
Let's find out if there is at least one value of t that makes both positions to be the same. We can try by equating one of the three coordinates and testing if the value of t make both have the same x,y,z coordinate. Let's try equating the x-components of both
Rearranging
Factoring
We found two solutions
for t=1 the x-coordinates are
For t=3
Now we'll test both values in the y-coordinates
For t=1
Thus they don't collide at t=1. Let's try t=3
Now let's try the z-coordinate for t=3
Since the three coordinates match, we can say both objects collide at t=3 in the point <9,9,9>
Answer:
B
Step-by-step explanation:
To find the y- intercept let x = 0
From the table for f(x)
When x = 0 → f(x) = - 4
That is the y- intercept = - 4
Given
g(x) = 3
let x = 0 , then
g(0) = 3 [
= 1 ]
= 3 × 1
= 3
That is the y- intercept = 3
Thus the y- intercept of g(x) is greater → B