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sveticcg [70]
3 years ago
7

The question is in the photo

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

8 goes in the first box

3 goes in the second box

The expression is \frac{8}{3}x^4y

==================================================

Work Shown:

z = 9xy * \left(\frac{2}{3}x\right)^3\\\\z = 9xy * \frac{2^3}{3^3}x^3\\\\z = 9xy * \frac{8}{27}x^3\\\\z = 9*\frac{8}{27}*x*x^3*y\\\\z = \frac{9*8}{27}*x^4y\\\\z = \frac{9*8}{9*3}*x^4y\\\\z = \frac{8}{3}x^4y\\\\

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Abraham is installing carpet in his bedroom. On the blueprints, Abraham's bedroom is 6 inches wide and 10 inches long. If the sc
erma4kov [3.2K]

Answer:

240 square feet

Step-by-step explanation:

Hello, I can help you with this

Step one

find the real scale

According to the data

scale is 1 in : 2 ft

also remember  1ft=12 inches

so

scale is 1in: 2(12 inches)

scale is 1 in :24 in

the purpose of use inches a unit in both sides is to eliminate the, the scale must be adimensional

so escales is

1:24  , this means, that a measure on the blueprint must be multiplied by 24 to know its real value

Step 2

with the escale find the real dimensions, you can use a rule of three

Abraham's bedroom is 6 inches wide

blueprint ⇔ bedroom

1 in ⇔ 24 in

6 in ⇔x

x=(6*24)/1

x=144 inches=12 ft

 Abraham's bedroom is  10 inches long

1 in ⇔ 24 in

10 in ⇔y

y=(10*24)/1

x=240 inches=20 ft

Step  3

find the area

the area is wide *long

area=x*y

area=12ft*20ft

area=240 square feet.

Have a good day

5 0
3 years ago
the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se
swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
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For a Giraffe with a leg length of 6 feet

S = √32×6

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For a Hippopotamus with a leg length of 3 feet

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S = √96

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Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0
2 years ago
What is the least common multiple of 2,6 and 15?
Alex

Answer:

LCM of 6 and 15 by Listing Multiples

Step 2: The common multiples from the multiples of 6 and 15 are 30, 60, . . . Step 3: The smallest common multiple of 6 and 15 is 30.

4 0
3 years ago
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Simplify open parentheses x to the 2 third power close parentheses to the 4 fifths power.
MissTica
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3 years ago
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Answer:

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