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3 years ago

9

2 to 10 as a fraction in lowest terms

1 answer:

Mamont248 [21]3 years ago

7 0

The answer to this problem is 1/5

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Write down the 1st term in the sequence given by: T(n) = n2 + 3

polet [3.4K]

If its first term, n is equal to 1. Thus...

T(1)=(1)(2)+3=2+3=5

The answer is 5.

7 0

3 years ago

Find the value of x in the solution to the system of equations shown.

ale4655 [162]

<span>y=4x-6
y=-4x+48
</span>4x-6= -4x+48
<span>0x=54
x=o</span>

8 0

4 years ago

1+3 what is 1 plus 3

Tems11 [23]

Answer:78.

I am just correct my guy

4 0

3 years ago

In a function, y varies inversely with x. The constant of variation is 4. Which table could represent the function?

Nimfa-mama [501]

The equation will be y=4/x. u can make the table of variables by inserting the values of x in the equation. for suppose here, if x=1 then y=4 , x=2 then y=2 and so on.

5 0

3 years ago

Read 2 more answers

A function h is defined by h(x)=−4x−72. If x decreases by 11, by how much does h(x) increase?

vladimir1956 [14]

<u>QUESTION 1</u>

The given function is

$h(x)=-4x-72$

If $x$ decreases by $11$ , then the new value is $x-11$ .

We need to find the value the function at $x-11$ which is

$h(x-11)=-4(x-11)-72$

This simplifies to

$h(x-11)=-4x+44-72$

The increment in $h(x)$ is given by;

$h(x-11)-h(x)=-4x+44-72-(-4x-72)$

This simplifies to,

$h(x-11)-h(x)=-4x+44-72+4x+72$

This further simplifies to

$h(x-11)-h(x)=44$

Therefore the corresponding increment in $h(x)$ is $44$ .

<u>QUESTION 2</u>

The given function is

$f(x)=\frac{3}{17}x+2$ .

If $x$ increases by $51$ , then the new value of $x$ is $x+51$ .

The increment in $f(x)$ is given by

$h(x+51)-h(x)=\frac{3}{17}(x+51)+2-(\frac{3}{17}x+2)$

We expand the brackets to get,

$h(x+51)-h(x)=\frac{3}{17}x+9+2-\frac{3}{17}x-2$

We simplify further to obtain,

$h(x+51)-h(x)=9$

Therefore the corresponding increment in $f(x)$ is $9$ .

7 0

3 years ago

Read 2 more answers