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Alik [6]
2 years ago
15

a daily newspaper had 12,125 subscribers when it began publications. Five years later it had 10,100 subscribers. What is the ave

rage yearly rate of change in the number of subscribers for the five year period?
Mathematics
1 answer:
Alex Ar [27]2 years ago
5 0
The reduction in the number of subscribers over 5 years is:
12,125 - 10,100 = 2025 lost subscribers.
The average yearly rate of change in the number of subscribers for the 5 year period is: -2025/5 = -405 subscribers/year.
The answer is: -405 subscribers/year.
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The Johnson family had a 4,392-gallon swimming pool installed last month. They are filling the pool at a rate of 2 pints per sec
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they are filling the pool every minute

7 0
2 years ago
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Please help! <br> How do you know if the domain or the range of a graph are all real numbers?
RideAnS [48]

Answer:

Many reasons

Step-by-step explanation:

Is there an asymptote?

Is there a whole?

Is it a vertical or horizontal line?

What's the specific function?

4 0
2 years ago
Let p(n) be the number of primes less than n. What is p(50)
Fofino [41]

Answer:

There are 15 prime numbers less than 50

Step-by-step explanation:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53

8 0
3 years ago
Please give me the right answer?
baherus [9]

(5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m)

P = 53/10 + 5 3/10 + 5 3/10 + 5 3/10

P = 53/10 + 53/10 + 5 3/10 + 5 3/10

P = 53/5 + 5 3/10 + 5 3/10

P = 53/5 + 53/10 + 5 3/10

P = 159/10 + 5 3/10

P = 159/10 + 53/10

P = 106/5

P = 21 1/5 meters

Answer: 21 1/5 meters (Decimal: 21.2m)

Hope that helps!!!! Have a great day!!!! : )

7 0
3 years ago
Plz help with the math worth 21 points
irinina [24]

Answer:

As there is one math problem over there.

Lets see the question first:

It says that "A hair dryer is rated 1200\ W,if you use the dryer for 0.25\ h.How much electric energy do you use ?"

Final answer = Electic energy =0.3\ kW\ h

Step-by-step explanation:

Electrical Energy E=Power \times time.

The total amount of electrical energy used depends on the total power used by the electrical device and the total time they are used for.

So we have been given the power of the hair dryer =1200\ W =\frac{1200}{1000}=1.2\ kW

Now the time it has been use for =0.25\ hrs

To calculate electric energy we will multiply both the terms.

Electric energy =0.12 \times 0.25 =0.3\ kW\ h

So electric energy used for the hairdryer is =0.3\ kW\ h

7 0
3 years ago
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