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Alik [6]
3 years ago
15

a daily newspaper had 12,125 subscribers when it began publications. Five years later it had 10,100 subscribers. What is the ave

rage yearly rate of change in the number of subscribers for the five year period?
Mathematics
1 answer:
Alex Ar [27]3 years ago
5 0
The reduction in the number of subscribers over 5 years is:
12,125 - 10,100 = 2025 lost subscribers.
The average yearly rate of change in the number of subscribers for the 5 year period is: -2025/5 = -405 subscribers/year.
The answer is: -405 subscribers/year.
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I WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
NemiM [27]

Answer:

- (x - 1) {}^{2}  + 5

Step-by-step explanation:

F(x) is a transformation from h(x).

So our starting equation is

- (x - 1) {}^{2}  - 1

F(x) is also facing the same direction h(x) is so we dont have to reflect nothing across the x or y axis.

There isn't a vertical or horizontal stretch, compressions.

There isn't a horizontal shift as the x values stay in the same place.

There is a vertical shift. We can simply move h(x) up 6 units to get to f(x).

So our equation looks like.

- (x - 1) {}^{2}  + 5

8 0
3 years ago
5 1/3 in decimal form​
STatiana [176]

Answer:

5.33

Step-by-step explanation:

5+1/3

=5.3333

=533.33333333%

7 0
3 years ago
Read 2 more answers
Antonio has $15 to spend on a set of colored pencils for his art class. Which number line represents the amount that he can spen
Mama L [17]
Answer: A
If he has 15$ then he could spend all of it on the colored pencils, so there has to be a black dot on 15, & if he could buy the colored pencils less than 15$ then it has to be a black dot on 15 & an arrow pointing to less than 15

I hope this answers your question
6 0
2 years ago
F(x)=9(x-8) find f^-1(x)
mina [271]

Answer:

f^{-1}(x) = \frac{1}{9} x + 8

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 9(x - 8) ← divide both sides by 9

\frac{y}{9} = x - 8 ( add 8 to both sides )

\frac{y}{9} + 8 = x

Change y back into terms of x with x = f^{-1}(x) , thus

f^{-1}(x) = \frac{1}{9} x + 8

8 0
3 years ago
Combine the following fractions by addition or subtraction as directed.
Marina86 [1]
Answer:\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}

Explanation:

Combining the fractions, we have:

\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\  \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\  \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\  \\ =\frac{-6(x+y)}{xy(x-y)} \\  \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}

8 0
1 year ago
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