The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.

1 answer:

3 0

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}$

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Does someone mind helping me with this? Thank you!

zalisa [80]

$\qquad\qquad\huge\underline{{\sf Answer}}$

The given two polygons are similar to one another ~

Sides of the given polygons are in ratio of :

$\qquad \sf \dashrightarrow \: 28 : 4$

to put in simple Ratio ~

$\qquad \sf \dashrightarrow \: 7: 1$

So, the sides of the larger polygon are :

4 × 7 = 28

6 × 7 = 42

3 × 7 = 21

4 × 7 = 28

7 × 7 = 49

3 × 7 = 21

3 × 7 = 21

4 × 7 = 28

Now, to find the Perimeter of larger polygon ~ add the side length of all sides :

$\qquad \sf \dashrightarrow \:p = 28 + 42 + 21 + 28 + 49 + 21 + 21 + 28$

$\qquad \sf \dashrightarrow \:238 \: \: units$

6 0

2 years ago

Here can someoen help me with this please

-Dominant- [34]

It'd be the first one.
Look at it like this:
3x2=6
6x2=12
12x2=24
24x2=48
48x2=96
96x2=192

4 0

3 years ago

Factor 1.21a^6+22a^3+100

Monica [59]

Answer:

$\frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100)$

Step-by-step explanation:

$1.21 {a}^{6} + 22 {a}^{3} + 100 \\ = 1.21 {a}^{6} + 11 {a}^{3} + 11 {a}^{3}+ 100 \\ = 11 {a}^{3} (0.11 {a}^{3} + 1) + 100(0.11 {a}^{3} + 1) \\ = (0.11 {a}^{3} + 1) (11 {a}^{3} + 100) \\ = ( \frac{11}{100} {a}^{3} + 1) (11 {a}^{3} + 100) \\ = ( \frac{11{a}^{3} + 100}{100} ) (11 {a}^{3} + 100) \\ = \frac{1}{100} (11 {a}^{3} + 100)(11 {a}^{3} + 100) \\ are \: the \: required \: factors.$