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____ [38]
2 years ago
13

Students in 7th grade took a standardized math test that they also had taken in 5th grade. The results are shown on the dot plot

, with the most recent data shown first. Find and compare the means to the nearest tenth. 7th-grade mean: 5th-grade mean: What is the relationship between the means?.
Mathematics
2 answers:
Finger [1]2 years ago
7 0

Answer: In general, the students increased their standardized math scores from 5th grade to 7th grade. The students might be more familiar with the exam and they have learned more in their math classes.

tensa zangetsu [6.8K]2 years ago
6 0

Answer:

7th grade mean: 16

5Th grade mean: 13.4

3. The 7th grade mean is about 2.5 points higher

Step-by-step explanation:

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In the game of​ roulette, a wheel consists of 38 slots numbered​ 0, 00,​ 1, 2,..., 36. To play the​ game, a metal ball is spun a
Oxana [17]

Answer:

E(X)=-0.0526

Sd(X)=5.763

Step-by-step explanation:

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.  

Let X be a random variable which denotes the money you may win or lose on each spin.

In the game of roulette, a wheel consists of 38 slots. To play the game, a metal ball is spun around the wheel and is allowed to fall into one of the numbered slots. If the number of the slot the ball falls into matches the number you selected, we win $35; otherwise we lose $1.  So we have just one possibility to win and 37 of lose on an individual game.

___________________________

X            P(X)

___________________________

35           1/38

-1            37/38

___________________________

In order to calculate the expected value we can use the following formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And if we use the values obtained we got:

E(X)=(35)*(\frac{1}{38})+(-1)(\frac{37}{38})=-0.0526

In order to find the standard deviation we need to find first the second moment, given by :

E(X^2)=\sum_{i=1}^n X^2_i P(X_i)

And using the formula we got:

E(X^2)=(35^2)*(\frac{1}{38})+((-1)^2)(\frac{37}{38})=33.211

Then we can find the variance with the following formula:

Var(X)=E(X^2)-[E(X)]^2 =33.211-(-0.0526)^2 =33.208

And then the standard deviation would be given by:

Sd(X)=\sqrt{Var(X)}=\sqrt{33.208}=5.763

4 0
3 years ago
5x^2-23x+12<br>this is the question im stuck on
AURORKA [14]
Rewrite it as 5x^2 -20x-3x+12
then (5x^2 -20x)(-3x+12)
then use gcf and u will get the answer in a binomial form
8 0
3 years ago
Help plz!!!!!!!!
VashaNatasha [74]
A(1.3) (3,1) idk if it’s right but seems like the right answer
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3 years ago
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Answer:

The upper one is 8, the lower one is 6

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