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Reil [10]
3 years ago
5

What is the length of BC¯¯¯¯¯ ?

Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Hello!


The length of side BC can be found by using the Law of Sines. This law states,

a / sin A = b / sin B = c / sin C.


Given:

Angle A = 51.2 degrees

Angle B = 60.3 degrees

Side AC (or B) = 21 cm

Side BC (or A) = ? cm


Let's plug in these values into the formula to find the missing side length.


a / sin (51.2) = 21 / sin (60.3)

a / sin (51.2) = 24.1759... (multiply both sides by sin(51.2)

a = 24.1759 · sin (51.2)

a = 18.841...


18.841 can be rounded to 19.


Therefore, the length of side BC is equal to 19 centimeters.

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Given: ∠AOC, ∠BOC - complementary angles
34kurt

Answer:

  • 30
  • COB . . . . or . . . . BOC

Step-by-step explanation:

The reason given on the line of interest is "substitution," so the problem boils down to determining what was substituted for what. The previous statement says ...

  AOC + COB = 90

and the first part of the statement we're to complete has BOC + ___.

We see from the given statements that m∠AOC = m∠BOC + 30°, so it appears that is the substitution that has been made: AOC has been replaced by BOC + 30.

This means the first blank is filled with 30.

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The second part of the previous statement is ...

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so we believe this (COB) should go in the second blank.

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Then the line of interest would read ...

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<em>Comment on the problem</em>

There is a curious mix of notations here. Usually, (as in the beginning of this problem) we refer to the measure of an angle using "m∠" in front of the angle designator, and we use a degree symbol to indicate the units of that measure. Part-way through the problem statement written here, those notations were dropped, and we're to assume they are intended. IMO, this is a poor way to demonstrate careful problem solving.

The substitution given for AOC is BOC+30, but the line into which that is substituted has AOC +COB = 90. This means the equation after substitution is ...

  BOC +30 +COB = 90

Since BOC and COB are the same angle, we can sort of fudge the "algebra" to get to  BOC=30, but if the problem were more carefully written, the angle would be referred to by consistent nomenclature:

  m∠AOC + m∠BOC = 90° . . . . . . . . . preferred angle designations

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  2(m∠BOC) = 60° . . . . . . algebra (subtract 30°, collect terms)

  m∠BOC = 30° . . . . . . . . algebra (divide by 2)

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