3 years ago

4×7.12 in distribitive property

Mathematics

1 answer:

bija089 [108]3 years ago

3 0

The answer will be 28.48

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Which two values of x are roots of the polynomial below?<br> 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

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3 years ago

"two angles are supplementary. the measure if one angle is 10 mire than three times the other. Find the measure of each angle.".

jolli1 [7]

If two angles are supplementary, their measures add to 180 degrees.

Let’s name the angles A and B.

You can substitute or replace angle B in the first equation with the second equation like so:

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So, angle A is 42.5 degrees and angle B is 137.5 degrees!

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Step-by-step explanation:

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