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3 years ago

13

Two spinners have been spun 100 times. Using the experimental probabilities below, what is the best guess for the number of time

s these spinners would land on the same number in 10 spins?

1 answer:

Agata [3.3K]3 years ago

3 0

It could be any time, but I would say 10. 10*10=100

hope it helps!

You might be interested in

Find the perimeter use 3.14

Alex777 [14]

Hey,
So we have to solve this in multiple steps. Step 1 is to find the circumference of the semi-circle and multiply by three since there are three. Step 2 would be to find the perimeter of the rectangle. Step 3 would be to add those two together.

Step 1: To find the circumference of the semicircle use the formula pi (3.14) times radius (8 ÷ 2 = 4) times 2. After that we will divide by two since there is only half. After that we will multiply that answer by three.
C = 3.14 x 4 x 2
C = 12.56 x 2
C = 25.12

C = 25.12 ÷ 2
C = 12.56

Perimeter = 12.56 x 3 = 37.68

Step 2: To find the perimeter of the rectangle/square add all the sides (8).
Perimeter = 8 + 8 + 8 + 8 = 32

Step 3: Now add the two previous answers to get the final perimeter.
37.68 + 32 = 69.68

Final Answer: 69.68
Hope this helped!

Cheers,
Izzy

8 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

Value of t? 1.4t — 0.4 (t — 3.1) = 5.8

IceJOKER [234]

Hi!

<h3>Use the distribution property</h3>

1.4t — 0.4 * t - 0.4 * —3.1 = 5.8

1.4t — 0.4t - 1.24 = 5.8

<h3>Simplify</h3>

1t - 1.24 = 5.8

<h3>Add 1.24 to both sides</h3>

1t - 1.24 + 1.24 = 5.8 + 1.24

1t = 7.04

<u>t = 7.04</u>

<h2>The answer is t = 7.04</h2>

Hope this helps! :)

-Peredhel

6 0

3 years ago

The daltons completed 30% of their 2140-mile trip the first day

Ugo [173]

To figure out how many miles the Daltons traveled the first day you times 2140 miles and 30 percent.
So 2140 x .30 = 642
They traveled 642 miles the first day.

To figure out how many miles they still have to travel you subtract your original miles (2140) from how many miles they have already traveled (642).
So 2140 - 642 = 1498
They have 1498 miles to still travel.

4 0

3 years ago

Read 2 more answers

This writing prompts is hard

Solnce55 [7]

A.) Simplifying the equation would lead you to 15x^2-3x+9

b.) You know your answer is correct because you're adding the two polynomials together. 9x^2+6x^2 is 1tx^2. Now you have 2x-5x and since the negative is bigger, you get -3x. Then 5+4 is 9. You have no like terms therefore your answer is 15x^2-3x+9

7 0

3 years ago