All categories

3 years ago

HELP What is the sum of 1000x and 2000x

Mathematics

2 answers:

____ [38]3 years ago

6 0

Steps to solve:

1000x + 2000x

~Combine like terms

3000x

Best of Luck!

stira [4]3 years ago

5 0

Answer:

$\huge\boxed{\sf 3000x}$

Step-by-step explanation:

Sum is Addition

$\sf 1000x + 2000 x \\\\x ( 1000 + 2000) \\\\x ( 3000) \\\\3000 x$

You might be interested in

Hellllllllllllllllllllllllllllppppppppppppppppp

dezoksy [38]

Answer:

Step-by-step explanation:

2.2x 5 = 11

6 0

3 years ago

Read 2 more answers

Write an exponential function for the graph that passes through the points (0,4) and (2, 36). Use the formula y=ab^x

fomenos

Answer:

Using the equation y = abx , substitute both of your given points into that equation.

2 = ab2 and 4 = ab3 Solve each equation for a.

2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3

Cross multiply: 2b3 = 4b2 Divide both sides by b2

2b = 4 a = 2/4 = 1/2

b = 2

y = 1 (2)x

Step-by-step explanation:

3 0

3 years ago

A basket ball player made 23 out of 50 free throws in the last game. What percent of the free throws did he make?

AlexFokin [52]

23/50 times 100= 46%

4 0

3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

6 0

3 years ago

In triangle ABC, cos A =

nikitadnepr [17]

The other expression that has a value of $\frac{7}{25}$ is A) sin B.

Step-by-step explanation:

Step 1:

$sin\theta = \frac{oppositeside}{hypotenuse} ,$ $cos\theta = \frac{adjacentside}{hypotenuse} ,$ $tan \theta = \frac{opposite side}{adjacent side} .$

For angle B, the opposite side measures 7 units, the adjacent side measures 24 units and the hypotenuse measures 25 units.

$sinB= \frac{oppositeside}{hypotenuse} = \frac{7}{25} ,$ $tan B = \frac{opposite side}{adjacent side} = \frac{7}{24} ,$ $cosB = \frac{adjacentside}{hypotenuse} = \frac{24}{25}.$

Step 2:

For angle A, the opposite side measures 24 units, the adjacent side measures 7 units and the hypotenuse measures 25 units.

$tan A = \frac{opposite side}{adjacent side} = \frac{24}{25} .$

Step 3:

tan C cannot be determined as C is the right angle. The opposite side and hypotenuse of the triangle would be the same.

So sin B also has a value of $\frac{7}{25}.$ This is option A.

7 0

3 years ago