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3 years ago

Find the scale factor.

Mathematics

1 answer:

charle [14.2K]3 years ago

6 0

Answer:

2/9

Step-by-step explanation:

Scale factor = 10/45 = 2/9

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Omg wow bruh #savageaf

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3 years ago

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Find the value of 4/5 divided by 8/15. You must simplify.

mrs_skeptik [129]

Answer:

3/2

Step-by-step explanation:

Assuming you meant fractions, to divide them, you must multiply the reciprocal of that fraction. You'll then have:

4/5x15/8

Reduce the numbers of the greatest common factor which is 5:

4x3/8

Reduce the numbers of the greatest common factor which is now 4:

3/2 is your answer

6 0

2 years ago

1) find the equation of the line parallel to

In-s [12.5K]

Answer:

1) The equation of the line parallel to x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is 2y = 5x -12

Solution:

1) find the equation of the line parallel to x-5y=6 and through (4,-2).

Given, line equation is x – 5y = 6

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}$

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }$

$y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14$

Hence, the line equation is 5y = x -14

2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)

$\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15$

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

$\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}$

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line $\times$ slope of given line = -1

slope of required line = $-1 \times \frac{5}{-2}=\frac{5}{2}$

And it passes through (2, -1)

Now, using point slope form

$\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}$

Hence, the line equation is 2y = 5x -12

4 0

3 years ago

4(g-1)=24 showing work

algol [13]

Answer:

g=7

Step-by-step explanation:

4(g-1)=24

g-1=6

g=6+1

g=7

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3 years ago

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Given mn, find the value of x. kt (3x-5) m → (2x-25) Please help me

oksano4ka [1.4K]

Answer:

I think this is the correct solution

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2 years ago

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