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Alborosie
3 years ago
6

Can you help me with this question

Mathematics
1 answer:
Naily [24]3 years ago
5 0
60% = $288
1% = 288/60 = 4.8
100% = 4.8 x 100 =48

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2 1/3 + 6 3/5

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3 years ago
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Carlton and Leon are expert bowlers. Seventy percent of Carlton's rolls are strikes, while 67% of Leon's rolls are strikes. Supp
IgorC [24]

Answer:

The probability that Leon strikes is greater than Carlton strike is 0.40905

Step-by-step explanation:

From the question, we have;

The percentage of Carlton's rolls are strikes, \hat p_1 = 70%

The number of games Carlton played, n₁ = 25

The percentage of Leon's rolls that are strikes, \hat p_2 = 67%

The number of games Leon played, n₂ = 25

Therefore, we have;

\hat p=\dfrac{k_1 + k_2}{n_1 + n_2}

Where;

k₁ = 0.7 × 25 = 17.5

k₂ = 0.67 × 25 = 16.75

\therefore \hat p=\dfrac{17.5 + 16.75}{25 + 25} = 0.685

The test statistic is given as follows;

Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p} \cdot (1-\hat{p})\cdot \left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}  \right )}}

Z=\dfrac{0.7-0.67}{\sqrt{0.685 \cdot (1-0.685)\cdot \left (\dfrac{1}{25}+\dfrac{1}{25}  \right )}} \approx 0.2283

From the z-table, we have;

The p-value for Carlton strikes is greater than Leon's strike = 0.59095

∴ The p-value for Leon strikes is greater than Carlton strike = 1 - 0.59095 = 0.40905

The probability that Leon strikes is greater than Carlton strike = 0.40905

8 0
3 years ago
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