Ok so basically, the number of student tickets is 3x, where x=the number of adult tickets sold. And we know that s(for student tickets)+x=480 total tickets sold. So if we replace s with 3x we have 3x+x=480, or 4x=480. We divide by 4 and get x=120, which is the amount of adult tickets sold.
Let the third side = x.
The sum of any two sides must be greater than the third side
14 + 9 > x
23 > x
14 + x > 9
x > -5
9 + x > 14
x > 5
So 5 < x < 23
Answer:
1?
Step-by-step explanation:
I think its one...
Answer:
no solution
Step-by-step explanation:
6x - 3y = 7 → (1)
- 2x + y = - 8 → (2)
multiplying (2) by 3 and adding to (1) eliminates the variables
- 6x + 3y = - 24 → (3)
add (1) and (3) term by term
0 + 0 = - 17
0 = - 17 ← false statement
This indicates the system has no solution
