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riadik2000 [5.3K]
3 years ago
13

Cuántas diagonales tendría una figura de 8 lados?

Mathematics
2 answers:
Alexus [3.1K]3 years ago
6 0
Son los 20 diagonales
Oduvanchick [21]3 years ago
3 0

Answer:      20 diagonales

Step-by-step explanation:

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In ΔPQR, the measure of ∠R=90°, QR = 91 feet, and RP = 26 feet. Find the measure of ∠Q to the nearest tenth of a degree.
trapecia [35]

Answer:

Step-by-step explanation:

answer

15.9454=15.9

5 0
3 years ago
Two circles of radius 1 are centered at $(4,0)$ and $(-4,0).$ How many circles are tangent to both of the given circles and also
galben [10]

Answer:

1 circle

Step-by-step explanation:

Given two circles (red circles on the diagram).

There are two tangent circles to both of the given circles (blue circles on the diagram), and only one of them is passing through the point (0,5).

Let's check it.

The equations of the tangent circles are

x^2+y^2=9\ [\text{Smaller tangent circle}]\\ \\x^2+y^2=25\ [\text{Larger tangent circle}]

Check whether point (0,5) lies on the smaller circle:

0^2 +5^2 =0+25=25\neq 9

No

Check whether point (0,5) lies on the larger circle:

0^2 +5^2 =0+25=25

Yes

<u>Answer: </u>1 circle

7 0
3 years ago
Jenny is saving money to buy a bike that costs $164. She has $52 and will save an additional $8 each week. In how many weeks wil
Aliun [14]

Answer:

14

Step-by-step explanation:

164 = 8x + 52

Subtract 52 from both sides

112 = 8x

Divide both sides by 8

14 = x

7 0
3 years ago
What is 25.0996 rounded to the nearest thousandth
madreJ [45]

Answer:

25.100

Step-by-step explanation:

The thousandth place is the third digit to the right of the decimal point - tenths is the first, hundredths is the second, thousandths is the third.  Since six rounds up and both nines round up, one must round up all of the way from the fourth decimal place to the tenth decimal place.

4 0
3 years ago
Jean transformed a point by using the rule (x,y)(x-6,y+8) the image point is (-4,1) which point is the pre image
Xelga [282]

To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).

(-4+6,1-8)

(2,-7) should be the pre image point.

8 0
4 years ago
Read 2 more answers
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