Answer:
Step-by-step explanation:
Number of students 10
Problem 1. $625 for the bus hire per friday, So 625*4=$2500
Problem 2. 2500/25=$100 each for the whole 4 weeks
Problem 3.
10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each
20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each
30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each
41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each
Hope this is correct
Answer:
-2 x (5x-12)
Step-by-step explanation:
Answer: positive
Step-by-step explanation: it’s positive because if you multiply two negative numbers they cancel each other out and it makes a positive number
![x+y=500](https://tex.z-dn.net/?f=x%2By%3D500)
![0.05x+0.085y=40 ](https://tex.z-dn.net/?f=0.05x%2B0.085y%3D40%0A)
Multiply both sides of second equation by 20 to get
![x+1.7y=800](https://tex.z-dn.net/?f=x%2B1.7y%3D800)
Subtract that from first equation to get
![0.7y=300](https://tex.z-dn.net/?f=0.7y%3D300)
Divide both sides by 0.7 to get
![y=428.571](https://tex.z-dn.net/?f=y%3D428.571)
, so about $428.57 was spent in store. This leaves
![500-428.57=$71.43](https://tex.z-dn.net/?f=500-428.57%3D%2471.43)
that was spent online