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3 years ago

If 8y+12=36 find the value of 2y

Mathematics

2 answers:

pashok25 [27]3 years ago

6 0

Answer:

Step-by-step explanation:

If 8y+12=36, subtract 36-12=24

Divide 24 by 8 and get three. 2y with y = 3 is 6

Tanya [424]3 years ago

5 0

Answer:

y=4 2(4)=8

Step-by-step explanation:

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Create a equation using this graph?

Setler79 [48]

The formula for a straight line is y=mx+b, where m is the slope and b is the y-intercept.

To find out the slope, we use a formula known as rise/run.

Rise means how high a point goes between any two points and run is how far the space is between any two points.

We can see that there are two points give to us. Now we ask our self how high do we have to go to reach the second points’ height. If we count it we go five UP. Meaning that the rise is positive 5.
Now we see how far the two points are. If we count it, we go 1 space the LEFT meaning -1 since going left on a graph means x is getting smaller.

Now that we have he two values, we put them into rise/run

5/-1=-5

So our value of m is -5
Meaning y=-5x+b

We still have our value of b to find and we can do this by choosing any one point on the graph and substituting it into the equation. We know that one of our points is (3,0)

We put these into the equation

y=-5x+b
0=-15+b
b=15

Therefore, y=-5x+15

7 0

3 years ago

A goal is to get at least 10% of daily calories from polyunsaturated fats as are found in various nuts, oils, and fish. One serv

natka813 [3]

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3 years ago

A carpenter wants to build a rectangular box with square sides in which to put round things. the material for the bottom costs $

alexira [117]

Answer: $1.627\times 1.627\times 1.88\ ft^3$

Step-by-step explanation:

Given

Suppose side face have a dimension of l\times l

and width of h

volume $V=l^2\cdot h$

$h=\frac{V}{l^2}$

volume $V=5 ft^3$

Area of side wall is $A_s=l^2$

Area of top Wall $A_t=l\times h$

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Cost of bottom wall $c_b=20\times l\times h=20lh$

Cost of top wall $c_t=50\times l\times h=50lh$

Cost of side walls $c_s=4\times l^2\times 10=40l^2$

total cost $C=c_s+c_t+c_b=20lh+50lh+40l^2$

$C=70lh+40l^2$

$C=70\times l\times \frac{5}{l^2}+40l^2$

differentiate C w.r.t l to get minima or maxima

$\frac{\mathrm{d} C}{\mathrm{d} l}=0$

$-\frac{350}{l}+80l^2=0$

$l^3=\frac{350}{80}$

$l=1.627 ft$

$h=\frac{5}{2.648}$

$h=1.88 ft$

Dimension of Box is $1.627\times 1.627\times 1.88\ ft^3$

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hammer [34]

Answer:

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