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3 years ago

Repost; I hate bots

Mathematics

1 answer:

Artyom0805 [142]3 years ago

5 0

Answer:

Bots are very annoying and they post inappropriate content too

Step-by-step explanation:

They need to be stopped

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1/4(x+3)+3/8x=13/4 SOLVE FOR X

larisa86 [58]

1. First I turned the fractions into decimals, just to make things easier for me.2. That gave me => (.25x)+(.75)+(.375)=(3.25)
3. Then, I combined like terms and move my equation around; so, that gave me (.25x) = (3.25) - (.75) - (.375) and when I solve the right side of the equation it gives me
(.25x) = (2.125)
4. After combining like terms and simplifying (the way I did in step 3), I will divide both sides by .25, to get the value of X alone; so, my equation then looks like => x=8.5

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3 years ago

Jsjbdiekek easy mathssss

aivan3 [116]

Answer: 6*x*y

Step-by-step explanation:

u have to do 2*3 first

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3 years ago

Read 2 more answers

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

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2 years ago

If you could switch two movie characters, what switch would lead to the weirdest movies?

Leviafan [203]

Answer:

Switching the Beast from Beauty and the Beast with Ariel From the Little Mermaid.

Step-by-step explanation:

Imagine the Beast being a merman o-o

6 0

3 years ago

Read 2 more answers

Robert mixed 113 liters of blue paint with 123 liters of red paint to make 3 liters of purple paint. To make a new batch of purp