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2 years ago

Please help me in this question question five and four fast as you can I want the area and conference of the circle thank you

Mathematics

1 answer:

ladessa [460]2 years ago

5 0

question for is 56 and quotation five is 135

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Please solve...Thanks

liberstina [14]

Micheal has 40ft of fencing for the rectangular dog run. So the perimeter of the dog run is 40ft.

Perimeter=40ft

The perimeter of a rectangle is:

P=2l+2w

Since we know the length is 5 and the perimeter is 40, we can solve for the width.

P=2l+2w
40=2*(5)+2w
40=10+2w
subtract 10 from both sides
30=2w
divide both sides by 2
15=w

The width of the fence is 15feet.

3 0

3 years ago

a small box in the shape of a cube has a length of 5 inches. how many cubic inches will the box hold?

Mama L [17]

Answer:

125 cubic inches

Step-by-step explanation:

volume of cube is l^3 so 5^3 is 125.

6 0

1 year ago

Read 2 more answers

Two trains arrived at a station at 2:55 P.M., with one arriving on Track A, and the other arriving on Track B. Trains arrive on

CaHeK987 [17]

The time before they will arrive together next is given by the LCM of 16 and 18 which is 144 minutes
2:55 PM + 2 h 24 minutes = 5.19 PM

Its B

4 0

2 years ago

The log of x cubed times y squared simplified

tresset_1 [31]

Answer:

$log(x^{3}y^{2}) = 3 log x+2 log y$

Step-by-step explanation:

Step 1:-

using logarithmic formula $log(ab)=log a+log b$

so given $log(x^{3} y^{2} ) = log (x^{3} )+log(y^{2} )$

now simplify

= $3 log x+2 log y$

<u>Answer:</u>-

$log(x^{3}y^{2})= [tex]3 log x+2 log y$

4 0

3 years ago

Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Fourteen people ans

Bond [772]

If Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week. Then the mean of the sample is 3.75.

The average of a group of numbers is simply defined as the mean. In statistics, the mean is regarded as one of the indicators of central tendency.

Sixty-five randomly selected car salespersons were asked the number of cars they generally sell in one week.

Fourteen people answered that they generally sell two cars; nineteen generally sell three cars; twelve generally sell four cars; nine generally sell five cars; eleven generally sell six cars.

Then the mean of the sample will be

$\rm Mean = \dfrac{1}{N} \times \Sigma _{i} \ \ x_if_i$

Then the table is given below.

Then we have

$\rm Mean = \dfrac{1}{65} \times (244)\\\\\\Mean = 3.7538\\\\Mean \approx 3.75$

More about the mean link is given below.

brainly.com/question/521501

#SPJ1

5 0

2 years ago