Question

An acute angle θ is in a right triangle with sin θ = five sixths. What is the value of cot θ?

Answer 1

I hope this helps you


sin(theta)=height/hypothenus



sin(theta)=5/6



base^2+height^2=hypothenus^2


base^2+5^2=6^2


base = sqrt 11


ctg (theta)= base/height


ctg (theta)=sqrt11/5

Answer 2

Assume the triangle has 3 sides with length of 5, 6, and sqrt(11)

So cotθ = 1/tanθ = 1/(5/sqrt(11)) = sqrt(11)/5