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3 years ago

12

Describe how you regroup when you find the sum of 64 + 43

1 answer:

vaieri [72.5K]3 years ago

4 0

When you regroup you are basically breaking down the problem.
You would do 60 + 40=?
Then you would do 4 + 3= ?
Your answer would come out to 107

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Serhud [2]

Letter B. Have a nice day

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3 years ago

Read 2 more answers

4. I need help with question in the attached picture!

Arisa [49]

ANSWER

D. 13

EXPLANATION

We have

$f(x) = \frac{2x + 1}{x - 4}$

To find

${f}^{ - 1} (3)$

means we want to find an x-value whose image is 3.

$\frac{2x + 1}{x - 4} = 3$

We cross multiply,

$2x + 1 = 3(x - 4)$

Expand:

$2x + 1 = 3x - 12$

Combine like terms,

$3x - 2x = 12 + 1$

$x = 13$

$\therefore{f}^{ - 1} (3)= 13$

4 0

2 years ago

Read 2 more answers

Mary sells to her father, robert, her shares in a corp for $55,000. the shares cost mary $80,000. how much loss may mary claim f

OverLord2011 [107]

Mary Purchase shares = $80,000
Mary Sells shares = $55,000

Loss she can claim for = $80,000 - $55,000
= $ 25,000

6 0

2 years ago

Write the ratio for sin P and cos Q

Gnom [1K]

Answer:

sin p -21/29

cos q 21/29 so here you go °~sohcahtoa~°

Step-by-step explanation:

sin means you find the soh part so you look for the oppisite over hyponuse

and for cos your looking for cah part so you find the adjsent over hypotnuse so the ansers is 21/29

4 0

2 years ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

2 years ago