Answer:
n+1
If a pyramid has n number of sides
⇒number of vertices in the base = n
Since in a pyramid there is one vertex on the top,and n number of faces are on the sides,and one face is in the base.
Total number of faces of pyramid = n+1
Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
Answer:
-sinx
Step-by-step explanation:
a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1
with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x
so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx
it is also important to know that cscx is the same thing as 1/sinx
knowing this information, cscx can be replaced with 1/sinx
(cos^2x)/(sinx - 1/sinx)
now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....
cos^2x
---------------------
(sin^2x - 1)/sinx
notice how in the denominator it has sin^2x-1 which is equal to -cos^2x
so now it becomes:
cos^2x
--------------
-cos^2x/sinx
because we have a fraction over a fraction, we need to flip it
cos^2x sinx
---------- * ----------------
1 - cos^2x
because the cos^2x can cancel out, it becomes 1
now the answer is -sinx
Answer:
y=5+2x
Normally I would explain it, but im in a bit of a hurry today. I apologize for the inconvenience!
