Answer:
4 + (3s/10) gallons
Step-by-step explanation:
Originally, there are 4 gallons. Add that to the expression. Every second, 3/10 gallon are filled. So s times 3/10 equal the total number of gallons added. Add both expressions together to get the answer.
Answer:
y=9b to the second power t over m
Step-by-step explanation:
should look like this
y=9b^2t/m
Call the smaller of the two odds = n
Call the next number in the sequence = n + 2
n*(n +2) = 782 Remove the brackets.
n^2 + 2n = 782 Subract 782 from both sides.
n^2 + 2n - 782 = 0 We are going to have to factor this.
Discussion
This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.
For example, you could use 783, (which factors) instead of 782 .
Solve
n^2 + 2n - 783 = 0
(n + 29)(x - 27) = 0
<u>Solution One</u>
n - 27 = 0
n = 27
The two odd consecutive integers are 27 and 29.
<u>Solution Two</u>
n + 29 = 0
n = - 29
The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.
Answer:
your answer is 415 in^3
Step-by-step explanation:
ok the equation in finding the volume of a come is
V= 
step 1: plugin
3.14 x 6^2 x 11/3
3.14x 36 x 11/3 = (6/3 turns into a 2)
113.04x 11/3= 114. 48, when rounded, it's going to give you 415 in^3
One worker<span> produces an average of 84 units per </span>day<span> with a street </span>What is the probability<span> that in any </span>single day worker 1 will outproduce worker 2<span>? A) 0.1141.
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Answer, factory worker productivity<span> is </span>normally distributed<span>. </span>One worker produces<span> an </span>average<span> of 75 </span>units per day<span> with a standar, day with a </span>standard deviation<span> of 20. </span>Another worker produces<span> at an </span>average rate<span> of 65 </span><span>per day.
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