<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
4p+9-7p+2=
group like terms
4p-7p+9+2
addd like terms
-3p+11
that is simplified form
Given that < 1 and < 3 are corresponding angles with the same measure, and that < 1 and m < 38 ° are supplementary angles in which their measures add up to 180°:
Then:
m< 1 + m < 38° = 180°
m < 1 = 180° — m < 38°
m < 1 = 142°
Since m < 1 = m < 3, then m < 3 = 142°
Is this 9x+4=5+5x or is it 9x•4=5•5x?
Answer:
504 miles
Step-by-step explanation:
you would do 756÷12 which equals 63.... For every hour that you drive its 63 miles. Then you do 63×8 to get 504
