
First, add all the numbers together. 
Divide by the amount of numbers. 
is the closest, so that is the answer.
A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb
</span>B) First, find the z-score:
z = (value - mean) / stdev
= (150 - 199) / 41
= -1.20
We need to find P(z > -1.20) = 1 - P(z < -1.20)
Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849
Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>
C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb
Let's repeat the steps of point B)
z = (187.5 - 199) / 41
= -0.29
P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141
</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%
D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
= 3750 </span></span><span>÷ 199
= 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
ok so 10 pennis is 1 dime which is 10 cents ok lets go to the next number 20 pennis will be 2 dimes because its the same cents then 30 pennis will be 3 and 40 will be 4 so just divide 10 into the number of pennis or in this case you have a easy out you can just use the numbers infront of the zero since you are talking about dimes.
It would even be the same if you had 2,300 pennis you would have 230 dimes
I think it is 989 or 899
*3 digit number*
*26 sum*
Last two digits are the same
Answer:
answer is in picture
Step-by-step explanation: