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KATRIN_1 [288]
3 years ago
8

Helpppppppppppppppp old!!!!!!!!!!!!

Mathematics
2 answers:
valina [46]3 years ago
6 0
Change all values to the same divisor:
8/12, 9/12, 7/12,10/12.

The questionis, which had the most left, so the smallest numerator.

7/12 is the smallest amount eaten.

Roast beef is your answer
notsponge [240]3 years ago
3 0
The answer is 7/12 because you can convert this into a decimal and also find the reduced number hope this helps
You might be interested in
22 out of the 55 teachers in a
wlad13 [49]

Answer:

40%

Step-by-step explanation:

Our fraction would be 22/55. You can divide and then multiply by 100 to get your percentage.

8 0
2 years ago
Can someone help me?<br> (if you can show your work that would be nice).
lubasha [3.4K]

Answer:

1. x1=15.75.

2. 24/48=0.5

3. 24/25=0.96

Step-by-step explanation:

1. 15.75/18=0.875

2. you multiply 48 times 0.5 to find 24.

3. multiply 0.96 with 25 to get 24.

3 0
3 years ago
1) Write a system of equations to describe the situation below, solve using any method, and
Aloiza [94]
This situation can be represented by

y = 33x + 223

y = 32x + 239

I still like substitution, so let’s plug in 33x + 223 into the second equation

33x + 223 = 32x + 239

Move the terms into appropriate sides

33x - 32x = 239 - 223

Combine like terms

x = 16

Then plug in x for any equation

y = 32(16) + 239

y = 751

Erin will have to swim 16 laps for a total of 751 meters
7 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
What is the length of the diagonal of the rectangle?
lapo4ka [179]

Answer:

21.25

Step-by-step explanation:

We can use the Pythagorean theorem to solve

We have the two legs and are looking for the hypotenuse

a^2 + b^2 = c^2

17^2 +12.75 ^2 = c^2  where c is the diagonal

289 +162.5625 = c^2

451.5625 = c^2

Take the square root

sqrt(451.5625) = sqrt(c^2)

21.25 =c

4 0
3 years ago
Read 2 more answers
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