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2 years ago

15

What the x?10x-45=7x

1 answer:

Olin [163]2 years ago

5 0

Answer:

15

Step-by-step explanation:

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Circle O has a circumference of 36pi cm

iogann1982 [59]

Circumference = 2 pi r , so

36 pi = 2 pi r

r = 36 pi / 2 pi

= 18 cm answer

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3 years ago

What is the value of x to the nearest tenth?

Oxana [17]

Actually the correct answer would be letter D. 89.7 mark as brainliest thanks

4 0

2 years ago

Subtract fractions with different denominators

Tems11 [23]

Answer:

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

Step-by-step explanation:

We know that

A fraction consists of two integers—one on the top, and one on the bottom.
The top one is numerator, the bottom one is denominator, and
These two numbers are separated by a line.

Let us consider two different fractions with different denominators

$\frac{10}{15}$

$\frac{2}{5}$

Lets subtract the two fractions

$\frac{10}{15}-\frac{2}{5}\:\:\:\:$

$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

so

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

5 0

2 years ago

Find the value of r 4(x-3)-r+2x=5(3x-7)-9x

vlabodo [156]

r = 4(x-3)/5(3x-7) + 11x

6 0

3 years ago

Find the equation of the quadratic function with vertex (-2,18) passing through (-5,0)?

Sliva [168]

Answer:

$y-18=-2(x+2)^2$

Step-by-step explanation:

Equation of the Quadratic Function

The vertex form of the quadratic function has the following equation:

$y-k=a(x-h)^2$

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

It's been given the vertex of the parabola as (-2,18):

$y-18=a(x+2)^2$

Now substitute the point (-5,0) and find the value of a:

$0-18=a(-5+2)^2$

Operating:

$-18=a(-3)^2$

$-18=9a$

Solving for a:

$a = -18 / 9$

a = -2

Thus, the equation of the quadratic function is:

$\mathbf{y-18=-2(x+2)^2}$

7 0

2 years ago