Hello :
<span>(27ax^3 – 9a^2x) ÷ 3ax :
</span> <span>(27ax^3 – 9a^2x) / 3ax
</span> (27ax^3 ) / (3ax) –( 9a^2x) / 3ax = 9x² - 3a
Answer:
y= 2/3x -1
Step-by-step explanation:
Ok so basically we want to put it in the form y=mx+b where m is 2/3 and passes through the point (9,5). So sub in the x and y of the point in brackets into the equation. 5= 2/3(9) + b and solve for b so b = -1. Therefore the equation is y=2/3x -1
Answer:
(x+1)^2 + (y-7)^2 = 2^2
Step-by-step explanation:
The center of the circle is at (-1,7) and the radius from the center to the edge is 2, so the equation should look like (x-h)^2 + (y-k)^2 = r^2
You would flip the signs of the center so that when you solve the equation it ends up in the correct place.
2(4^2 + 1) = 2(16+1) = 2(17) = 34
