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Nikitich [7]
3 years ago
7

Determine the equation of the circle graphed below .

Mathematics
1 answer:
Volgvan3 years ago
3 0

Answer:

(x+1)^2 + (y-7)^2 = 2^2

Step-by-step explanation:

The center of the circle is at (-1,7) and the radius from the center to the edge is 2, so the equation should look like (x-h)^2 + (y-k)^2 = r^2

You would flip the signs of the center so that when you solve the equation it ends up in the correct place.

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IS THIS CORRECT?! I HAVE A BACK SIDE TOO, IF ANYTHING IS WRONG PLS PLS LMK!!
Fudgin [204]

The only error you made is on problem 3. Everything else is correct. Nice work.

-------------------------------------------------------

Here is how to solve problem 3

Plug x = 1 into the equation and solve for y

-3x + y = 1

-3*1 + y = 1 ... replace x with 1

-3 + y = 1

y - 3 = 1

y - 3 + 3 = 1 + 3 .... add 3 to both sides

y = 4

<h3>The answer is 4</h3>

-------------------------------------------------------

Verifying the answer:

Plug (x,y) = (1,4) into the equation. Both sides should be the same number after simplifying both sides.

-3x + y = 1

-3*1 + 4 = 1 ..... replace x with 1; replace y with 4

-3 + 4 = 1

1 = 1

The answer is confirmed.

If you were to graph -3x + y = 1, which is equivalent to y = 3x+1, you'll find that the point (1,4) is on this line.

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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