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Doss [256]
3 years ago
15

How do you solve for y in this equation?

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0
Use photo math it will explain what you have to do
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THIS IS FUNNY
yaroslaw [1]

Answer:

thats funny lol :)

Step-by-step explanation:

8 0
2 years ago
Solve the following equation: lim x->0 sin3x/5x^3-4x.
goblinko [34]
Usual limit of sin is sinX/X--->1, when X--->0

sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x=                    [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
   =(sin3x / 3x) . (3/5x^2- 4)
finally lim  sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
                 x----->0            x---->0
3 0
3 years ago
Tuesday and Wednesday work
AURORKA [14]
Prime factorizations - Wednesday work
1. 44     2^2 • 11
2. 125    5^3
3. 85     5 • 17
4. 39     3 • 13
5. 63     3^2 • 7
6. 240    2^4 • 3 • 5
7. 87     3 • 29
8. 45     3^2 • 5
8 0
3 years ago
If x is 1 what is the value of y?9x - 5y = 29
mylen [45]

Given

The equation,

9x - 5y = 29.

To find the value of y when x is 1.

Explanation:

It is given that,

9x-5y=29

That implies,

When x=1,

\begin{gathered} 9(1)-5y=29 \\ 9-5y=29 \\ -5y=29-9 \\ -5y=20 \\ y=\frac{20}{-5} \\ y=-4 \end{gathered}

Hence, the value of y is -4.

4 0
1 year ago
Town C is 2 miles east of town A and 2 miles south of Town B as in the figure at right. which of the following is the best estim
Ray Of Light [21]
Since C is 2mi east of A and 2mi south of B, the shortest distance from A to B would be a straight line which is equal to the hypotenuse of a right triangle with a base of 2mi and a height of 2mi..

d^2=x^2+y^2

d^2=2^2+2^2

d^2=4+4

d^2=2*4

d=√(2*4)

d=2√2 mi  (exact)

d≈2.83 mi  (to nearest hundredth of a mile)
5 0
3 years ago
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