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3 years ago

Using the guess and check technique, find two numbers that satisfy both conditions.

Mathematics

2 answers:

maksim [4K]3 years ago

7 0

Answer:

Step-by-step explanation:

21 X 2 = 42

42-7 = 35

35 + 21 = 56

kvv77 [185]3 years ago

4 0

Answer:

B is definitely the answer

Step-by-step explanation:

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For EACH ordered pair, determine if its a solution to 2x+9y=13

vladimir1956 [14]

The answer is (2,1). 2*2=4 and 9*1=9. 9+4=13

8 0

3 years ago

1/(x-2)+1/(x+3)=1/5 solve the problem for me

Gennadij [26K]

════════ ∘◦❁◦∘ ════════

<h3>Final value : x² -9x - 11</h3>

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$\frac{1}{(x - 2)} + \frac{1}{(x + 3)} = \frac{1}{5}$

$\frac{(x + 3) + (x - 2)}{(x - 2)(x + 3)} = \frac{1}{5}$

$\frac{2x + 1}{ {x}^{2} + 3x - 2x - 6 } = \frac{1}{5}$

$\frac{2x + 1}{ {x}^{2} + x - 6} = \frac{1}{5}$

2x + 1 = ⅕ × (x² + x - 6)

2x + 1 = ⅕x² + ⅕x - 6/5

1/5x² +1/5x - 2x - 6/5 - 1 = 0

1/5x² -9/5x - 11/5 = 0

x² - 9x - 11 = 0. #times by 5

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#Give me brainliest pls im tired typing all of this

8 0

3 years ago

Tank 1 initially contains 50 gals of water with 10 oz of salt in it, while tank 2 initially contains 20 gals of water with 15 oz

Naddik [55]

$\dfrac{\mathrm dx_1}{\mathrm dt}=\dfrac{2\text{ oz}}{1\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac{x_1(t)\text{ oz}}{50\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}-\dfrac{x_2(t)\text{ oz}}{20\text{ gal}}\dfrac{5\text{ gal}}{1\text{ min}}$

$\implies\begin{cases}\dfrac{\mathrm dx_1}{\mathrm dt}=10-\dfrac1{10}x_1\\\\\dfrac{\mathrm dx_2}{\mathrm dt}=\dfrac1{10}x_1-\dfrac14x_2\\\\x_1(0)=10\\\\x_2(0)=15\end{cases}$

6 0

3 years ago

1. The manager of FrozonAir Refrigerator factory notices that on Monday it cost the company a total of $25,000 to build 30 refri

Vinvika [58]

Answer:

The fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

Step-by-step explanation:

Let

Cost per refrigerator (marginal cost) = r

Fixed costs per day for the factory = f

Total cost = variable cost + fixed cost

Monday

25,000 = 30r + f

Tuesday

30,000 = 40r + f

Using Monday,

f = 25000 -30r

Substitute f = 25000 - 30r into Tuesday

30,000 = 40r + f

30,000 = 40r + (25,000 -30r)

30,000 = 40r + 25,000 - 30r

Collect like terms

30,000 - 25,000 = 40r - 30r

5,000 = 10r

Divide both sides by 10

r = 5,000 / 10

= 500

r = $500

Substitute r= 500 into Monday equation

f = 25,000 -30r

= 25,000 - 30(500)

= 25,000 - 15,000

= 10,000

f = $10,000

Therefore, the fixed costs per day for the factory is $10,000 and marginal cost of one refrigerator for $500

7 0

3 years ago

Solve for the missing item in the following. (Do not round intermediate calculations. Round your answer to the nearest cent.)

iogann1982 [59]

9514 1404 393

Answer:

$1904.76

Step-by-step explanation:

The interest formula is ...

I = Prt . . . . interest on principal P at rate r for t years

Solving for P, we find ...

P = I/(rt) = 200/(0.07·1.5) = 200/0.105 ≈ 1904.76

The principal amount was $1904.76.

7 0

2 years ago